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Simplify the following Boolean expressions, using Boolean Algebraic rules:





ABC' + A'BC + ABC + A'BC'

(BC' + A'D) (AB'+ CD')

ABC' + A'BC + ABC + A'BC'
= AB(C'+C) + A'B(C+C')

=AB + A'B

=B(A+A')


=B

(BC'+A'D)(AB'+CD')

=BC'AB' + BC'CD' + A'DAB' + A'DCD'


=AC'+BD'+B'D+A'C

=AC'+A'C=0

=BD'+B'D=0

=0+0

=0